1) Abridged problem statement
- There are n participants and m football matches.
- For each match, the actual result (a, b) is given, followed by n predictions (p_i, q_i), one per participant.
- Scoring per prediction:
  - +2 if the outcome (win/draw/loss) is correct.
  - +3 if the goal difference a - b is correct.
  - +1 if the first team’s goals a are correct.
  - +1 if the second team’s goals b are correct.
- Output the total score for each participant after all matches.

2) Detailed editorial
- Observations:
  - The score is additive across four independent checks per match: outcome, difference, first team goals, second team goals.
  - If the exact score is guessed, all four conditions hold, awarding 2 + 3 + 1 + 1 = 7.
  - If the difference is correct, the outcome is automatically correct as well, including the draw case (difference 0). Still, both bonuses are awarded, per the rules.
- Algorithm:
  - Read n, m.
  - For each match:
    - Read actual result (a, b).
    - For each participant i:
      - Read prediction (p, q).
      - Initialize score = 0.
      - Outcome: if (a > b and p > q) or (a < b and p < q) or (a == b and p == q), add 2.
      - Difference: if (a - b) == (p - q), add 3.
      - First team goals: if a == p, add 1.
      - Second team goals: if b == q, add 1.
      - Accumulate to participant i’s total.
  - Print all totals.
- Correctness:
  - The above directly implements the scoring rules independently. Every condition is checked exactly as specified.
- Complexity:
  - Time: O(n·m), at most 100·100 = 10,000 predictions; trivial within limits.
  - Memory: O(n·m) if all predictions are stored; can also be done streaming with O(n) memory, but not necessary.

3) Provided C++ solution with detailed comments
#include <bits/stdc++.h>              // Include all standard C++ headers (GNU extension).
using namespace std;                   // Avoid prefixing std:: everywhere.

// Overload stream output for pair<T1, T2>: print "first second".
template<typename T1, typename T2>
ostream& operator<<(ostream& out, const pair<T1, T2>& x) {
    return out << x.first << ' ' << x.second;
}

// Overload stream input for pair<T1, T2>: read "first second".
template<typename T1, typename T2>
istream& operator>>(istream& in, pair<T1, T2>& x) {
    return in >> x.first >> x.second;
}

// Overload stream input for vector<T>: read each element in order.
template<typename T>
istream& operator>>(istream& in, vector<T>& a) {
    for(auto& x: a) {
        in >> x;                      // Uses T's operator>> (e.g., pair<int,int>).
    }
    return in;
};

// Overload stream output for vector<T>: print elements separated by spaces.
template<typename T>
ostream& operator<<(ostream& out, const vector<T>& a) {
    for(auto x: a) {
        out << x << ' ';              // Prints each element followed by a space.
    }
    return out;
};

// Global input parameters and storage.
int n, m;                              // n = number of participants, m = number of matches.
vector<pair<int, int>> actual;         // actual[match] = (a, b) actual result for each match.
vector<vector<pair<int, int>>> predictions; // predictions[match][i] = (p, q) predicted by participant i.

// Read all input into the above containers.
void read() {
    cin >> n >> m;                     // Read number of participants and matches.
    actual.resize(m);                  // Prepare storage for actual results.
    predictions.resize(m);             // Prepare storage for predictions per match.

    for(int match = 0; match < m; match++) {
        cin >> actual[match];          // Read actual result (a, b) for this match.
        predictions[match].resize(n);  // Prepare storage for n predictions for this match.
        cin >> predictions[match];     // Read all n predictions for this match.
    }
}

// Compute scores and output results.
void solve() {
    // Simple direct implementation following the scoring rules.
    vector<int> scores(n, 0);          // scores[i] accumulates total score of participant i.

    for(int match = 0; match < m; match++) {
        int a = actual[match].first;   // Actual goals by first team.
        int b = actual[match].second;  // Actual goals by second team.

        for(int i = 0; i < n; i++) {
            int p = predictions[match][i].first;   // Predicted goals by first team.
            int q = predictions[match][i].second;  // Predicted goals by second team.

            int score = 0;             // Score for this participant on this match.

            // Outcome (winner or tie) guessed correctly?
            if((a > b && p > q) || (a < b && p < q) || (a == b && p == q)) {
                score += 2;
            }

            // Goal difference guessed correctly?
            if(a - b == p - q) {
                score += 3;
            }

            // First team's goals guessed correctly?
            if(a == p) {
                score += 1;
            }

            // Second team's goals guessed correctly?
            if(b == q) {
                score += 1;
            }

            scores[i] += score;        // Add this match's score to participant i's total.
        }
    }

    cout << scores << '\n';            // Output all participants' scores (with trailing spaces), then newline.
}

int main() {
    ios_base::sync_with_stdio(false);  // Speed up I/O.
    cin.tie(nullptr);                  // Untie cin from cout for faster input.

    int T = 1;                         // Single test case (kept as a variable for convenience).
    // cin >> T;                       // If multiple tests existed, we'd read T.

    for(int test = 1; test <= T; test++) {
        read();                        // Read all input for this test case.
        // cout << "Case #" << test << ": "; // (Not used, per problem statement.)
        solve();                       // Solve and print the result.
    }

    return 0;                          // Exit program.
}

4) Python solution with detailed comments
import sys

def main():
    data = list(map(int, sys.stdin.read().split()))  # Read all integers from stdin.
    it = iter(data)                                   # Create an iterator for sequential reading.

    try:
        n = next(it)                                  # Number of participants.
        m = next(it)                                  # Number of matches.
    except StopIteration:
        return                                        # Empty input; nothing to do.

    # Initialize total scores for all participants.
    scores = [0] * n

    # Process each match.
    for _ in range(m):
        # Read the actual result (a, b).
        a = next(it)
        b = next(it)

        # For each participant, read prediction and compute score contribution.
        for i in range(n):
            p = next(it)
            q = next(it)

            add = 0

            # Outcome correct (winner or draw)?
            if (a > b and p > q) or (a < b and p < q) or (a == b and p == q):
                add += 2

            # Difference correct?
            if (a - b) == (p - q):
                add += 3

            # First team's goals correct?
            if a == p:
                add += 1

            # Second team's goals correct?
            if b == q:
                add += 1

            scores[i] += add

    # Output the scores separated by spaces.
    print(' '.join(map(str, scores)))

if __name__ == "__main__":
    main()

5) Compressed editorial
- For each match and participant, compute four independent bonuses:
  - +2 if outcome (win/draw/loss) matches,
  - +3 if goal difference matches,
  - +1 if first team goals match,
  - +1 if second team goals match.
- Sum these across all matches per participant and print. Complexity O(n·m), with trivial constants.