1. Abridged Problem Statement  
-----------------------------  
Given a principal s, a term of m months, and a monthly interest rate p percent, compute the fixed annuity payment x so that after m equal payments the debt is fully repaid. Output x with an absolute error up to 1e-5.

2. Detailed Editorial  
---------------------  
We want a constant monthly payment x such that, if the remaining debt before month i is Sᵢ, then each month:  
  – interest portion: aᵢ = (p/100) · Sᵢ  
  – principal portion: bᵢ = x – aᵢ  
  – next debt: Sᵢ₊₁ = Sᵢ – bᵢ  

We must have S₁ = s and Sₘ₊₁ = 0.  

Case p = 0: no interest accrues, so x = s / m.  

Case p > 0: let r = p/100. We can write the update  
  Sᵢ₊₁ = Sᵢ – (x – r·Sᵢ) = (1 + r)·Sᵢ – x.  

Unrolling this recurrence for m steps yields  
  Sₘ₊₁ = (1 + r)ᵐ·s – x·[ (1 + r)ᵐ⁻¹ + (1 + r)ᵐ⁻² + … + 1 ].  

We require Sₘ₊₁ = 0, so  
  x · [((1 + r)ᵐ – 1)/r] = (1 + r)ᵐ · s  
⇒ x = s · [r·(1 + r)ᵐ] / [ (1 + r)ᵐ – 1 ].  

Compute (1 + r)ᵐ via fast exponentiation (pow), then apply the formula in O(1) time.  
Be careful with floating-point precision; use double and set output precision to five decimal places.

3. C++ Solution with Line-by-Line Comments  
-------------------------------------------  
```cpp
#include <bits/stdc++.h>
using namespace std;

// Compute the monthly payment for an annuity loan.
// s: initial debt (principal), m: number of months, p: interest rate (percent per month)
double findMonthlyPayment(double s, int m, double p) {
    // If interest rate is zero, it's just principal divided evenly
    if (p == 0.0) {
        return s / m;
    }
    // Convert percent to decimal
    double r = p / 100.0;  
    // Compute (1 + r)^m
    double factor = pow(1.0 + r, m);
    // Numerator: r * (1 + r)^m
    double numerator = r * factor;
    // Denominator: (1 + r)^m - 1
    double denominator = factor - 1.0;
    // Annuity formula: s * [r*(1+r)^m] / [(1+r)^m - 1]
    return s * numerator / denominator;
}

int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);

    // Read input: s (principal), m (months), p (percent interest)
    double s;
    int m;
    double p;
    cin >> s >> m >> p;

    // Compute the monthly payment
    double x = findMonthlyPayment(s, m, p);

    // Print with exactly 5 digits after decimal point
    cout << fixed << setprecision(5) << x << "\n";
    return 0;
}
```

4. Python Solution with Detailed Comments  
-----------------------------------------  
```python
import sys

def find_monthly_payment(s, m, p):
    """
    Calculate the fixed annuity payment per month.
    s: principal (float or int)
    m: number of months (int)
    p: monthly interest percentage (float)
    """
    # If there's no interest, split the principal evenly
    if p == 0:
        return s / m

    # Convert percentage to decimal rate
    r = p / 100.0
    # Compute (1 + r)^m
    factor = (1 + r) ** m
    # numerator = r * (1 + r)^m
    numerator = r * factor
    # denominator = (1 + r)^m - 1
    denominator = factor - 1.0
    # Annuity payment formula
    x = s * numerator / denominator
    return x

def main():
    # Read three values from standard input
    data = sys.stdin.read().strip().split()
    s, m, p = map(float, data)  # m can be float-cast but behaves as int
    m = int(m)
    # Compute payment
    x = find_monthly_payment(s, m, p)
    # Output with 5 decimal places
    print(f"{x:.5f}")

if __name__ == "__main__":
    main()
```

5. Compressed Editorial  
-----------------------  
- If p=0, answer is s/m.  
- Else let r=p/100; compute factor=(1+r)^m.  
- Use x = s·[r·factor]/(factor−1).  
- Print x with five decimal digits.