1. Abridged Problem Statement
Given two positive integers A and B (1 ≤ A, B ≤ 10 000), compute and output their sum.

2. Detailed Editorial
Problem restatement
• You are given two integers A and B, each between 1 and 10 000. You must compute A + B and print the result.

Constraints and implications
• A, B up to 10 000 → their sum is at most 20 000, well within a 32-bit int.
• Only two numbers → time complexity O(1), memory footprint negligible.

Solution approach
1. Read two integers from standard input.
2. Compute their sum using built-in integer addition.
3. Print the result to standard output.

Implementation details
• In C++ you can use cin/cout or scanf/printf. Because the input is tiny, performance is trivial.
• In Python you can use input().split() to parse the two numbers and then print their sum.
• No edge cases beyond ensuring the inputs are parsed correctly—negative numbers are not allowed by the statement.

Complexity
• Time complexity: O(1).
• Memory complexity: O(1).

3. C++ Solution
```cpp
#include <bits/stdc++.h>

using namespace std;

template<typename T1, typename T2>
ostream& operator<<(ostream& out, const pair<T1, T2>& x) {
    return out << x.first << ' ' << x.second;
}

template<typename T1, typename T2>
istream& operator>>(istream& in, pair<T1, T2>& x) {
    return in >> x.first >> x.second;
}

template<typename T>
istream& operator>>(istream& in, vector<T>& a) {
    for(auto& x: a) {
        in >> x;
    }
    return in;
};

template<typename T>
ostream& operator<<(ostream& out, const vector<T>& a) {
    for(auto x: a) {
        out << x << ' ';
    }
    return out;
};

int a, b;

void read() { cin >> a >> b; }

void solve() {
    // Read two integers and print their sum.

    cout << a + b << '\n';
}

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);

    int T = 1;
    // cin >> T;
    for(int test = 1; test <= T; test++) {
        read();
        // cout << "Case #" << test << ": ";
        solve();
    }

    return 0;
}
```

4. Python Solution
```python
# Read a line from standard input, split into tokens, convert to integers
a, b = map(int, input().split())

# Compute the sum of the two integers
result = a + b

# Print the result
print(result)
```

5. Compressed Editorial
Read two integers (≤ 10 000), add them, and print the result. Time and space complexities are both constant.
